#1 : 09/03-20 11:33 jack nguyen
Posts: 2
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Can you help me rename like this
1 -> ex1 2 ->ex1A 3 ->ex1B 4->ex1C 5->ex1D 6->ex2 7->ex2A 8->ex2B 9->ex2C 10->ex2D 11->ex3 .... .... .... 15->ex4 16->ex4A ...... 20->ex5 .... Thank you so much |
#2 : 09/03-20 20:39 David Lee
Posts: 1125
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The following script will do what you ask:
n = item.name; m = Math.ceil(n / 4); a = (n - 1) % 5; b = (a) ? String.fromCharCode(a + 64) : " "; return "ex" + m + b; This assumes that your filenames are simple numbers, as in your example. If not then you will have to be more specific. |
#3 : 15/03-20 06:27 jack nguyen
Posts: 2
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Reply to #2:
thank you so much |