numbering a batch of files

in ascending order.

I love your program, should have known someone would come up with this great tool ;) I am trying it out and have files numbered 19 through 24 but will all sorts of junk I don't need in the name. I add the files, put in the name (but just the first which would be 19). After that I click on Add Method but I can't get the filename to be anything but 19 for all files. I just want them to be 19, 20, 21, 22, 23, and 24.

Could someone show me how to do this? I found a couple of posts on renaming files, with perfect answers for the 2 people that knew/understood the code. So I need someone to put it in simpler terms for me til I get the hang of the program. Thanks in advance for anyone that might be able to help me.

You question doesn't make much sense so I'll have to try to guess what you are trying to do!

I assume that each filename contains one of these two-digit numbers buried in other characters and you wish to rename the files with just the two-digit numbers.

You will need to use the Replace method with a Regular Expression - the section in the User Guide should give you enough information to solve the problem: https://www.advancedrenamer.com/user_guide/regul ar_expresions

However - to get you started...

First to extract ANY 2-digit number use the pattern: .*(\d{2}).*

Each ".*" will match a string of characters of any length (including zero).
"(\d{2})" will match a string of two digits and enclosing in parentheses means that the match will be saved in the variable \1 - so the Replace string will be \1

However the "*" modifier is "greedy" and the first ".*" will match as many characters as possible before moving on to select the two digits. So if you have more than two pairs of digits, or a string of more than two digits, this will return the latest possible match.

eg abc223def will return 23

Adding "?" after the "*" will reverse this behaviour and make the modifier "lazy" so it will match the minimum number of characters and the match will return the first pair of digits

so .*?(\d{2}).* will return 22 in the above example.

If you need to match ONLY the two digit numbers from 19 to 24 you can use the OR character - "|" - in the regular expression.

eg the regular expression .*?(19|20|21|22|23|24).* will return the first instance of any one of these numbers, in the variable \1

I hope this explanation is sufficiently clear.