Randomize by groups

I have 4,000+ files with the following name pattern:

13182496371
13182510187
13182558569-001
13182558569-002
13182558569-003
13182558569-004
13182809809

I want add a 3-character random name and keep groups/sets:


AWD
FWG
GHF-001
GHF-002
GHF-003
GHF-004
HEJ

Any ideas? I know I have to use <Rand Str:3> but it does not keep groups. Thanks!

You will need to use a script to keep track of the previous filenames.

A simple answer to your problem is the script:

suffix = item.name.match(/-\d{3}$/);
n = suffix * -1;
if (n < 2) {txt = app.parseTags('<Rand Str:3>')}
return txt;

You must ensure that the files are sorted in ascending order and set the Name collision rule to "Append number" and separator to "-".

The .match method extracts the value of the numeric suffix. If there is no suffix or it has the value "-001" then the tag "<Rand Str:3>" is used to define a new filename and this value is stored in the variable txt. If the suffix is "-002" then the previously saved value of txt is used as a filename. The suffix is recreated by the collision rule.

However there is a problem with this solution. Whilst <Rand Str> will produce a pseudo-random string each time it runs, you need to be aware that Advanced Renamer does NOT keep track of which strings have been used. Hence there is a possibility of duplicates - particularly if you have a large number of filenames - since there are only 17,576 possible permutations of a three-letter string.

You must keep track of which permutations have already been used and keep generating new permutations until <Rand Str> returns an unused value.

The following script should solve the problem:

In the Pre batch script:

var test = [];
for (j = 0; j < 17575; j++) {
test[j] = 0;
}

function getText() {
do {
n1 = Math.floor(Math.random() * 26);
n2 = Math.floor(Math.random() * 26);
n3 = Math.floor(Math.random() * 26);
n = n1 + (n2 + n3 * 26) * 26;
}
while (test[n]);
test[n] = 1;
return String.fromCharCode(n1 + 97) + String.fromCharCode(n2 + 97) + String.fromCharCode(n3 + 97);
}

and in the main script window:

suffix = item.name.match(/-\d{3}$/);
n = suffix * -1;
if (n < 2) {txt = getText()}
name = txt;
if (suffix) {name = name + suffix}
return name;

Reply to #1:
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