#1 : 22/11-20 11:52 Armaan
Posts: 2
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I am unable to move #\d+ (#1, #12 etc) to start of line.
What it means the move count lable, if I choose to be it in RegEx.? Modern JavaScript Tutorial #3 - Control Flow ---> #3 Modern JavaScript Tutorial - Control Flow PHP Tutorial #37 - Null Coalescing ---> #37 PHP Tutorial - Null Coalescing |
#2 : 22/11-20 15:46 David Lee
Posts: 1125
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The following works for me:
Replace: (.*)(#\d+ ) With: \2\1 Make sure you are selecting "Use regular expressions" |
#3 : 23/11-20 08:34 Armaan
Posts: 2
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Reply to #2:
Thanks a lot.. It works what does it means \2\1? would you like to explain me. |
#4 : 23/11-20 09:53 David Lee
Posts: 1125
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Reply to #3:
See the User Guide: www.advancedrenamer.com/user_guide/regular_expresions |