#1 : 06/04-13 14:31 NomenEtOmen
Posts: 29
|
hi,
i try to remove end-positioned digits, which are in brackets like: my folder name (123) other folder (10) digit-lenght 1-3; i tried this remove pattern method: $\(d{1-3}\) case-sensitive: no use reg ex: yes apply to: name and ext but no success. also the more general $\(d+\) brings no effect. where i'm wrong? can anyone help? thx a very pleased user |
#2 : 06/04-13 21:32 Kim Jensen
Administrator
Posts: 883 |
Reply to #1:
Please give me an example of the filename you want to rename and an example of the result you want after the rename batch. |
#3 : 07/04-13 20:49 NomenEtOmen
Posts: 29
|
Reply to #2:
ok, here an example: original directory name with ending digits in brackets: "any directory name (456)" should be renamed to: "any directory name" in general, ending (digits) of the length of 1 to 3 should be removed. |
#4 : 07/04-13 22:42 Kim Jensen
Administrator
Posts: 883 |
Reply to #3:
Your regex pattern should be \(\d+\)$ |
#5 : 09/04-13 13:31 NomenEtOmen
Posts: 29
|
Reply to #4:
yeah, it works. and for a more specific determination the digit-length-limitation with \(\d{1,3}\)$ works also well. but an other "error" occurs: i have in the workload list a lot of dir entries, but only a few matches with this pattern and get an new name. so the renamer works fine until i "start batch". the renamer does the renaming well, but the resulf info window prompts with an error count of exact the number of entries which should NOT be renamed. it's a little confusing because the confidence in the renaming will be decreased. ciao |
#6 : 20/06-15 21:57 Kalroz
Posts: 5
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Reply to #4: Hello. I have the similar problem, and tried your suggestions, but this is not working.
The difference is that in the end of file name I have dot, like this: Garden of my dreams.123456 or Garden of my dreams .123456 Thanks' in advance. ***************************** Sorry, I founded the pattern, that is in replace mode: Text to be replaced: (.+)(.{7}) Replace with: /1 Use regular expressions: Check It's work in this case. |